Question

x^2+6x+11
can be as (x+p)^2+q
where p and q are integers to be found

Answer 1

The task is to create a perfect square trinomial using the given terms:

x^2+6x+11

= (x^2+6x + 9) + 11 - 9

= ( x + 3) ^ 2 + 2 so p = 3 and q = 2

To get the 9, take half of 6 and square it. To maintain equality, subtract it after forming the perfect square trinomial.

Answer 2

thank you my dear

Answer 3

Glad to help

Answer 4

y-3x+2=0
y^2-x-6x^2=0
a simultanious equation