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Mathematics 9 Online
OpenStudy (anonymous):

3^(x^2+x)=√3

OpenStudy (freckles):

\[3^{x^2+x}=3^\frac{1}{2}\]

OpenStudy (freckles):

set exponents equal dude!! :)

OpenStudy (freckles):

\[x^2+x=\frac{1}{2}\]

OpenStudy (anonymous):

Essentially what freckles said; you can set them to be equal by taking the log_{3} of both sides.

OpenStudy (freckles):

freckles is such a cute name :)

OpenStudy (anonymous):

Too bad you don't have a complimentary picture.

OpenStudy (anonymous):

The answer you gave me is different than the one in my book

OpenStudy (anonymous):

x^2+x-0.5=0, use quadratic formula to obtain x=(-1±√(3))/2

OpenStudy (freckles):

\[x^2+x-\frac{1}{2}=0 => 2x^2+2x-1=0\]

OpenStudy (freckles):

ok what bad said

OpenStudy (anonymous):

...Or do what freckles did.

OpenStudy (freckles):

:)

OpenStudy (anonymous):

ahh this is so confusing

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