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Physics 18 Online
OpenStudy (anonymous):

I need help finding the relationship of the resistors in the circuit. I am not sure which are parallel and which are part of a series...See the attached image. Thanks

OpenStudy (anonymous):

sorry hold on. having trouble with the image. one sec!

OpenStudy (anonymous):

OpenStudy (anonymous):

If R4 wasn't there I would say that those two lines are two series in parallel...

OpenStudy (anonymous):

Since its given that current in R4 is 0 you can remove R4.

OpenStudy (anonymous):

Then later on when I need to determine Rx I will use?

OpenStudy (anonymous):

It becomes a balanced wheatstone bridge. R2/R1=RX/R3.

OpenStudy (anonymous):

wheatstone bridge? I suppose I should do a search on that.

OpenStudy (anonymous):

But those two series groups are indeed parallel, correct?

OpenStudy (anonymous):

yeah thats correct. The condition for i4=0 is the condition i have stated above

OpenStudy (anonymous):

imaginary "i"? Haven't incorporated that into my circuit knowledge yet but okay. Thanks for your help!

OpenStudy (anonymous):

imaginary??

OpenStudy (anonymous):

i4

OpenStudy (anonymous):

Oh you mean R4

OpenStudy (anonymous):

i4=0. It ain't imaginary current though R4 is zero. How on eartch do you say its imaginary?

OpenStudy (anonymous):

Oh you mean capital I... as in current

OpenStudy (anonymous):

yeah... lol

OpenStudy (anonymous):

ch'yeah

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