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Let y= 3x^2 + 6x +2 Find the differential dy when x=5 and dx= 0.3 Find the differential dy when x=5 and dx= 0.6
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dy= 6x dx + 6 dx now plug in values for x and dx
oh now i get it you set it up as a proportion....
dy/dx = (6x+6)/.3 right?
normally we think of dx as an infinitesimal, but here they are not.
I think it is dy/dx = 6x+6 or dy= (6x+6) * dx
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oh ok
oh i always forget to put the dx after i take a derivative
normally you put the dx in the denominator i.e. dy/dx = d f(x) so the dx is on the left-hand side.
Thank you guys! :D
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