Question

(8x)/(x^2+4x+4)/(4x^2)/(x^2-4) in simplified form???

Answer 1

\[\frac{8x}{x^2+4x+4}\times \frac{x^2-4}{4x^2}\]

Answer 2

we can cancel right away a bit, but can also factor

Answer 3

\[\frac{8x(x-2)(x+2)}{4x^2(x+2)(x+2)}\]

Answer 4

cancel away and get
\[\frac{2(x-2)}{x(x+2)}\]

Answer 5

Wow thank you so much :) Can I ask you about one more? x^2-36 /x+6 I think it's x-6 but I don't know what the restriction would be?

Answer 6

yes you are right

Answer 7

What would the restriction be?

Answer 8

6 or -6?

Answer 9

x cannot be -6