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Let f(x)= 2x^2+2x-12/ x-3 show tht ƒ(x) HAS A REMOVABLE DISCONTINUITY AT X=2 AND DETERMINE VALUE FOR ƒ(2) would make ƒ(x) continue at x=2 Must define f(2)=??? I tried to plug in 2 for x values after factoring, but the answer i think it was wrong :)
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Is the answer 10? I just need a further proof!
\[f(x)\frac{2x^2+2x-12}{x-3}\]This function is continuous at x=2. Unless I have the function or point wrong. The function is discontinuous at x=3 though.
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