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f'(x)= 200 - 1600/(x + 8) - x
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...You want to find f(x), the antiderivative? f(x)=200x-1600ln(x+8)-(1/2)x^2
no the derivative
f ' (x)
You yourself already wrote "f'(x)=200-1600/(x+8)-x", which is the derivative of f(x). The derivative of f'(x) is f''(x), which is f''(x)=1600/(x+8)^2-1.
i wrote f (x) but want to the deriv f ' (x) of that function
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not the 2nd deriv
I quote you, "f'(x)= 200 - 1600/(x + 8) - x". That's what you originally wrote. f'(x).
ah whatever!! lets just find the deriv
I already gave it, then, except wrote it as f''(x). The derivative of the function you gave me is (d/dx)(200-1600/(x+8)-x)=1600/(x+8)^2-1
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