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When you drive a car around a curve that is not banked, what force provides the centripetal acceleration? HINT: Think about turning a curve on ice. If the curve is banked, what additional force plays a role in providing the centripetal force? Draw force diagrams to clarify your thinking
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The friction force of the tires provides a centripetal force. The normal force of the car contributes to the centripetal force on a banked turn. This is why we can set the bank of a road such that no friction between the road and tires are required to make the turn at a specific speed.
so would the force diagram look something like this |dw:1329976139117:dw|
Remember to include all relavent forces. |dw:1329976421662:dw|
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