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Mathematics 20 Online
OpenStudy (anonymous):

express all trigonometric in terms of cos*alpha*

OpenStudy (anonymous):

\[\cos \alpha\]

OpenStudy (anonymous):

sin (alpha) = SQRT(1-cos^2(alpha)) tan (alpha) = SQRT(1-cos^2(alpha))/cos(alpha) And so forth.....

OpenStudy (anonymous):

isnt there a simple way? like cos(alpha) = tan/sen or something like that??

OpenStudy (anonymous):

Not if you want to express in terms of cos. tan = sin/cos cot = cos/sin sec = 1/cos cosec = 1/sin But, sin = SQRT(1-cos^2). So, all the rest have to follow that way.

OpenStudy (anonymous):

Or, you can use this relationship between sin and cos: sin(q)=cos(q- p/2) or equivalently cos(q)=sin(q+ p/2).

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