Question

Solve:
1=(3)/(x+3)+(18)/(x-3)^(2)

Thx ;)

Answer 1

\[\frac{3}{x+3}+\frac{18}{(x-3)^2}=1\]
\[\frac{3(x-3)^2+18(x+3)}{(x+3)(x-3)^2}=1\]
\[3(x^2-6x+9)+18x+54=(x+3)(x-3)^2\]
\[3x^2-18x+27+18x+54=(x+3)(x^2-6x+9)\]
\[3x^2+81=x^3-6x^2+9x+3x^2-18x+27\]
\[x^3-6x^2-9x-54=0\]

Answer 2

sure it wasn't (3)/(x-3)

Answer 3

Ooh waoo, Thx.. :)

Answer 4

its not solved yet...

Answer 5

http://www.wolframalpha.com/input/?i=solve+for+x%3A+x%5E3-6x%5E2-9x-54%3D0

Answer 6

you sure you typed your question right?

Answer 7

it is not solved...somenthing is wrong ://

Answer 8

Ohh, I am so sorry... its x+3 on both sides..

Answer 9

that makes it much easier...you should make sure you type your question right if you want the right answer

Answer 10

\[\frac{3}{x+3}+\frac{18}{(x+3)^2}=1\]
This is your problem?

Answer 11

Yes, Thx again.

Answer 12

(x+3)^2 is the LCD
\[\frac{3(x+3)+18}{(x+3)^2}=1\]
\[3x+9+18=(x+3)^2\]
\[3x+27=(x+3)^2\]
\[3x+27=x^2+6x+9\]
\[x^2+3x-18=0\]
\[(x+6)(x-3)=0\]
x=-6, 3

Answer 13

Thumb up!! Thx.

Answer 14

3 ( x+3) + 18 = ( x+3) ^2
3x + 27 = x^2 + 6x + 9
-> x^2 + 3x - 18 = 0
=>( x + 6) ( x -3) = 0
Thus x = -6, x = 3