Question

f(x)=e^(x+4lnx)
find f'(6).

Answer 1

that's about 871,406.2

Answer 2

can your work and i need 2 decimal places

Answer 3

*show

Answer 4

*sigh.* I'm just a mite bit busy with my hw...but the decimals are .19, I'm pretty sure.

Answer 5

thats not the answer...
ive been having trouble with problem all day.

Answer 6

*this

Answer 7

f(x)=e^(x+4lnx)
f'(x) = e^(x+4lnx) * (x+4lnx)'
(x+4lnx)' = 1 + 4/x
f ' (x) = e^(x+4lnx) * (1 + 4/x)

Answer 8

f'(6) = e^(6+4ln6) * (1 + 4/6) = e^(6+4ln6) * (10/6)

Answer 9

f'(6) = e^(6+4*ln6) * (10/6) = 2160e^6

Answer 10

o my god! that is correct!

Answer 11

THANKS!

Answer 12

np

Answer 13

dude, really?
typo the whole time?

Answer 14

lol not really. i never use parenthesis.

Answer 15

i was copy pasting turing.. where's the typo?

Answer 16

he was talking to me

Answer 17

ohh ok

Answer 18

http://openstudy.com/study#/updates/4f468279e4b065f388ddfdce