Mathematics
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OpenStudy (anonymous):
What quadrant do the solutions lie in?
1) 3x – 2y = 10
5x + 3y = 4 A) I
2) 3x + 2y = 14
x – 3y = –10 B) II
3) x + 2y = 8
4x + 6y =22 C) III
4) 2x + 3y = –12
4x – 2y = –2 D) IV
14 years ago
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OpenStudy (anonymous):
graph the pair of lines and see where the intersection lies in
14 years ago
OpenStudy (anonymous):
I have trouble solving these equations.
14 years ago
OpenStudy (anonymous):
Systems ... do you know how to solve systems of EQ?
14 years ago
OpenStudy (anonymous):
Kind of
14 years ago
OpenStudy (anonymous):
are you allowed to use a graphing calc at school?
14 years ago
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OpenStudy (anonymous):
I do online school.
14 years ago
OpenStudy (anonymous):
would you like me to show you how to solve systems of equations?
14 years ago
OpenStudy (anonymous):
1) 3x – 2y = 10
5x + 3y = 4
-> (2, -2) in the fourth quadrant
14 years ago
OpenStudy (anonymous):
I want to know the main key point in knowing how to solve problems like this.
14 years ago
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OpenStudy (anonymous):
points*
14 years ago
OpenStudy (anonymous):
you're looking for the intersection of the two lines ... to find this you can use Substitution Method, Elimination Method, Graphing Method or Matrices
14 years ago
OpenStudy (anonymous):
Okay, I've herd of Substitution Method. What do you do for this step?
14 years ago
OpenStudy (anonymous):
Solve for one of the variables ... y = .....
14 years ago
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OpenStudy (anonymous):
2) 3x + 2y = 14
x – 3y = –10
-> (2, 4) in the first quadrant!
14 years ago
OpenStudy (anonymous):
and plug it in the second equation and solve for x
14 years ago
OpenStudy (anonymous):
try solving for y in the first eq 1st system
14 years ago
OpenStudy (anonymous):
What do you plug in?
14 years ago
OpenStudy (anonymous):
Random numbers?
14 years ago
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OpenStudy (anonymous):
did you solve for y?
14 years ago
OpenStudy (anonymous):
No
14 years ago
OpenStudy (anonymous):
let's do that first:
14 years ago
OpenStudy (anonymous):
3) x + 2y = 8
4x + 6y =22
-> ( -2, 5) in the second quadrant
14 years ago
OpenStudy (anonymous):
do you know how to solve for y?
14 years ago
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OpenStudy (anonymous):
Nope
14 years ago
OpenStudy (anonymous):
ok ... here we go :
14 years ago
OpenStudy (anonymous):
3x-2y =10
14 years ago
OpenStudy (anonymous):
subtract 3x from both sides
14 years ago
OpenStudy (anonymous):
-2y = 10-3x
14 years ago
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OpenStudy (anonymous):
divide by -2
14 years ago
OpenStudy (anonymous):
y= -5 +3/2x
14 years ago
OpenStudy (anonymous):
4) 2x + 3y = –12
4x – 2y = –2
-> ( -15/8, -11/4) in the third quadrant!
14 years ago
OpenStudy (anonymous):
this is solving for y... now we have an expresion for y we can substitute y in the second eq with the expression for y we just found
14 years ago
OpenStudy (anonymous):
5x+3y=4 substitute the y with -5+3/2x
14 years ago
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OpenStudy (anonymous):
we get : 5x + 3(-5+3/2 x) = 4 ...
14 years ago
OpenStudy (anonymous):
solve for x
14 years ago
OpenStudy (anonymous):
5x-15 +(9/2)x=4
14 years ago
OpenStudy (anonymous):
Here I like the same denominator ...(10/2)x -30/2 +(9/2)x=8/2
14 years ago
OpenStudy (anonymous):
now eliminate the denominator
14 years ago
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OpenStudy (anonymous):
10x-30+9x=8
14 years ago
OpenStudy (anonymous):
combine like terms
14 years ago
OpenStudy (anonymous):
19x =38 -> x=2
14 years ago
OpenStudy (anonymous):
substitute 2 in y=-5+(3/2)x , y=-5+3 =-2 the solution (2,-2)...(IV quad)
14 years ago
OpenStudy (anonymous):
watch the video ...I think you'll understand better
14 years ago
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OpenStudy (anonymous):
also use iTunes U for algebra videos ...awesome resource
14 years ago
OpenStudy (anonymous):
are you still here ?
14 years ago
OpenStudy (anonymous):
Yeah I'm here :-)
14 years ago
OpenStudy (anonymous):
Thanks for helping me understand this a little bit better.
14 years ago
OpenStudy (anonymous):
good ... did you understand ?
14 years ago
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OpenStudy (anonymous):
use khanacademy ... Sal is good at explaining
14 years ago
OpenStudy (anonymous):
Lol okay :-)
14 years ago
OpenStudy (anonymous):
have fun ... <3Math
14 years ago