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Mathematics 14 Online
OpenStudy (anonymous):

Given: DA, TO, and CG are all medians of Triangle DOG. Find x Find y Find AG Find DA

OpenStudy (anonymous):

OpenStudy (accessdenied):

You know that those are medians, so they bisect all three outer sides. We are given the lengths of half of two of the sides. We also figured out that this was a right-triangle. If we use this information with the pythagorean theorem, we can find the unknown side.OG which is twice the length of AG because the median bisects that side

OpenStudy (accessdenied):

* unrelated, you were correct by saying x = 8 *

OpenStudy (anonymous):

So DO equals 7, DG equals 25, and I would do 7 squared + x = 25 squared? 49 + x = 625 x=sqrt 576 x = 24?

OpenStudy (anonymous):

well not x, but OG

OpenStudy (accessdenied):

Yes, 24 would be the length of OG... so AG is half.

OpenStudy (accessdenied):

We also can see that DOA is a right triangle. We just figured out the OG, and OA is equal to AG...

OpenStudy (anonymous):

is it the square root of 193?

OpenStudy (accessdenied):

Yes, that is what I got.

OpenStudy (anonymous):

Thanks for all your help :) Now all I have is left are some proofs, but I can do that on my own. Thank you

OpenStudy (accessdenied):

No problem! I hope you aren't going to just give up and fail now! :P

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