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Mathematics 14 Online
OpenStudy (anonymous):

help see attached file

OpenStudy (anonymous):

OpenStudy (ash2326):

rini I'm gonna guide you in this, you'll have to solve it. Would you do that?

OpenStudy (anonymous):

yes

OpenStudy (ash2326):

Find y in terms of x from second equation

OpenStudy (anonymous):

13,12

OpenStudy (ash2326):

rini?

OpenStudy (anonymous):

x=13 y=12

OpenStudy (anonymous):

correct?

OpenStudy (anonymous):

How come my response vanished?

OpenStudy (ash2326):

Yeah, you'll get two values for x and y. we have to choose which one lies in 1st quadrant. (13,12) is the answer

OpenStudy (anonymous):

thanks again! anxwer:(13,12)

OpenStudy (anonymous):

The way to get it is to notice that (x^2 - y^2) = (x+y)(x-y). Since (x+y) = 25, (x-y) must be 1. So, you have: x - y = 1 x + y = 25 => 2x = 26 => x = 13 => y = 12

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