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Mathematics 73 Online
OpenStudy (anonymous):

Please look at attachment.

OpenStudy (anonymous):

OpenStudy (anonymous):

that was wrong..;p

OpenStudy (anonymous):

It can equal all of those

OpenStudy (anonymous):

If 1 were an option, I'd say 1 because it's a horizontal asymptote

OpenStudy (dominusscholae):

\[(x+2)/(x+1)\] is the same as 1 + \[2/(x+1)\]. Since \[2/(x+2)\] is never equal to zero, we want to find which number to set the original rewritten equation to so that \[2/(x+1)\] equals zero. 1 satisfies this requirement. (E).

Directrix (directrix):

I say E) 1 because the x+2 can never be equal to x +1. So, their ratio never equals one.

OpenStudy (anonymous):

Do you guys see an E in the attachment? I don't

OpenStudy (anonymous):

SAT drives me crazy with its hard problems -.-

OpenStudy (anonymous):

unless my computer is broken

OpenStudy (dominusscholae):

You can also say that there is a vertical asymptote is at x= -1 for the graph and get the same answer. And yes I see a e. lol.

OpenStudy (anonymous):

I see a big gray area under D

OpenStudy (anonymous):

Does E say 1?

Directrix (directrix):

The thing about these SAT problems is that quick solutions are required (usually) and are possilbe. The way of thinking is not the way we usually learn this stuff in math class. That's not a bad thing - just the way it is. Some people prefer the ACT because it is more achievement oriented - so they say.

OpenStudy (dominusscholae):

Yes.

OpenStudy (anonymous):

Ah, then E is the answer lol

OpenStudy (dominusscholae):

Either way its a test, so in the end nobody cares lol.

OpenStudy (anonymous):

OpenStudy (anonymous):

thats what i see lol

OpenStudy (dominusscholae):

yep might just be your browser. I am on chrome.

OpenStudy (anonymous):

Oh, haha, maybe something is wrong with your computer :P

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