The allele for a widow’s peak has complete dominance over the allele for a straight hairline (w). What is the probability of two parents heterogeneous for a widow’s peak (Ww) having an offspring without a widow’s peak? Answer 0% 25% 50% 75%
I am going to help you with just one of your questions. Users tend to get more out of the site when they treat it as a tutoring experience and post questions one at a time. They also tend to get more out of it when they include in their post a guess or tell us what specifically about the question is not understood. The question tells you that both parents are heterozygous - that is, Ww - for widow's peak. That means that each child has a 25% chance of being homozgyous dominant; a 50% chance of being heterozygous and a 25% chance of being homozygous recessive. That is, 25% + 50% = 75% of offspring will have a widow's peak and 25% won't. In this case, homozygous recessive corresponds to the phenotype - no widow's peak - which you want the probability of, so the correct answer is 25%. Clear?
Im sorry it just that i just found this site today and ive had this homework for a while and didnt know how to do it :/
the correct answer is not 25%
So wait, what IS the correct answer??
Idk, I just had this question on a test and 25% is what I put and I got it wrong.
@iKitlen
@RAINBOWDASHROCKS
i keep getting 25 percent
I got 75%?
Meeeeh im the odd one out LOL
but it says without a widow peak
I know. I still got 75%.
really?
how
Really really. I might just be doing it wrong, but thats what I got.
WW 25% Ww Ww 50% ww 25% these r my results
@RAINBOWDASHROCKS
@RAINBOWDASHROCKS
I gtg soon tho
75%
alright ill try both and see which one works
thanks guys
no prob
Np.
Join our real-time social learning platform and learn together with your friends!