compute the derivative of f(x) = (x^2 -3x- sqrt(x)/ sqrt(x)
please show all calc involved
F'(x)=-3+2 x
x^2 = 2x , -3x = -3, sqrt(x)/sqrt(x) = 1, 1= 0
i dont think she meant that
i think she meant all of the top over all of the bottom
u = x² -3x -√x --> u' = 2x -3 - 1/2√x v = √x ---> v' = 1/2√x = (2x -3 - 1/2√x) √x - [ (x² -3x -√x) 1/2√x ] / x = 3x (x -1)/ 2x^(3/2)
f'(x) = (3 x-3)/(2 sqrt(x))
Common denominator is 2√x
Jinnie, I don't have that version of MS office on this laptop!
\[\frac{x^2-3x-\sqrt{x}}{\sqrt{x}}\]
@Jinne, could you check my u = ... , v = .... If it's right then my answer's correct!
Thanks a bunch Mertsj :), then I'm correct!
So my answer is correct, yes?
I'm double check my work, rmrj!
can anyone view the attachment I posted
yes i saw ur document, couldnt see what your choice for D) was
my choice for d and e are 2x-1, 2x-3, respectively
I can't! Could you just type it up!
cholorphyll. give me a bit of time. i can switch computers. i can't type it out because its too funky.
I'm double check my calculation, anyway! I just broke my powerful laptop, so now I'm using the antique one :(
It's C
merts are you sure. when i tried this i came up with b
can you demonstrate please?
Sorry to hear about that Cholorophyll. I broke my laptop as well so I have to walk on campus to use the schools computer for everything
"walk" , for real in this freezing weather... :'(
Bottom times derivative of top is \[x ^{\frac{1}{2}}(2x-3-\frac{1}{2}x ^{\frac{-1}{2})}\]
I live like a 5 mins distance plus my roomate somtimes give me a ride. not so bad
-top times derivative of bottom IS: \[-(x^2-3x-x ^{\frac{1}{2}})(\frac{1}{2}x ^{\frac{-1}{2}})\]
Put those two together and you have your numerator.
Put all of that over x which is the denominator squared
Now let's distribute and simplify
That's correct, so you take denominator is 2√x from inside the parentheses, then distribute with √x out side
I don't see any flaw in my calculation!
\[2x ^{\frac{3}{2}}-3x ^{\frac{1}{2}}-\frac{1}{2}x ^{0}-\frac{1}{2}x ^{\frac{3}{2}}+\frac{3}{2}x ^{\frac{1}{2}}+\frac{1}{2}x ^{0}\]
remember this is all over x
Now collect the like terms.
\[\frac{3}{2}x ^{\frac{3}{2}}-\frac{3}{2}x ^{\frac{1}{2}}\]
Remember that is all over x so now divide each term by x
\[\frac{3}{2}x ^{\frac{1}{2}}-\frac{3}{2}x ^{\frac{-!}{2}}\]
Choice C
ok thanks
Ok. Now I'll check it with Wolf
What the result, Mertsj?
Is it 3 (x -1)/ 2 √x
\[\frac{3\sqrt{x}}{2}-\frac{3}{2\sqrt{x}}\]
Which is exactly what I said albeit in a slightly different form.
Your answer is the same thing chlorophyll
Yep, just in add together, --> (3x -1)/ 2√x
That would be 3x-3
I mean 3(x -1)/ 2√x
Happy, Jinnie :)
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