p^2-8p+7 still dont understand please explain!
What factors of 7 add up to get -8?
Can you please post the full question. We are not clear what you are confused about.
how to factor it
Well one easy way to see it is if you have p^2 alone then you can factor it simply by (p) * (p) but we have all these extra things next to p^2 so we have to expand (p) * (p) so we can have it equal out
@Daniela, In this case, 1 - 8 + 7 = 8 - 8 = 0 => 1 root p = 1, and other is 7 ( c/a = 7/1)
There are methods to finding the extra stuff but I'm bad at explaining that so hopefully someone else can help
@Romeo, you're much better explainer than I'm
wait I got confused
I usually liked the "what factors of [constant term] add up to get [linear coefficient]?" explanation for when you have the leading coefficient of one on p*2 i.e. You have four factors of 7: 1, 7 and -1, -7 both work -7 and -1 add up to -8, which is our linear term. If we used these values in a factored form... (p - 7)(p - 1) p(p - 1) - 7(p - 1) then we can check through distributing again p^2 - p - 7p + 7 <--- those middle terms are our factors! p^2 - 8p + 7
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