write (solve for) a polynomial with the following zeros
a) 2 and -3i

Question

write (solve for) a polynomial with the following zeros 
a) 2 and -3i

nenadmatematika · Answer

on of the polynomials is (x-2)(x^2+9)

anonymous · Answer

Can you explain how you got that answer please?:) thanks!

nenadmatematika · Answer

if 2 is the zero of the polynomial then that polynomilal can be divided with (x-2) without rest....if 3i is the zero, then it's dividable with (x-3i)....you must know that 3i is the complex zero, and there is always one friend following him...it's -3i so this polynomial is dividable with (x-(-3i))=x+3i.....now you can multiply all the parenthesis and you get your polynomial....(x-2)(x-3i)(x+3i)....those last two give the difference of the squares...so you can write it as I did above....of course, you can multiply them also...:D

anonymous · Answer

You are amazing! Thanks :)

nenadmatematika · Answer

if you'd like to see if you got this right, I can give you one example, and you can solve it here....check this one out....|dw:1330286335128:dw|