A batter hits a baseball upward with an initial speed of 96 feet per second. After how many seconds does the ball hit the ground? Use the formula h = rt - 16t2 where h represents height in feet and r represents the rate in feet per second.

Question

mertsj · Answer

$$0=96t-16t^2$$

mertsj · Answer

$$-16t(t-6)=0$$

mertsj · Answer

$$t=6$$

anonymous · Answer

0 = 96ft/s * t - 16 t^2

16t^2 = 96t
16t = 96
t = 96/16 = 6

mertsj · Answer

The ball hits the ground after 6 seconds.

anonymous · Answer

At the time the ball hits the ground means h = 0
-> h = - 16t² + 96t = 0
->  16 t ( -t + 6 ) = 0
=> t = 6 sec for the ball to land  ( omit t = 0 as start time)