Question

NEED an answer ASAP!!!!!!!! I know that you can change this 1/(x^2(x+1)) into:
1/x^2 +1/(x+1) -1/x
However, I dont know how, could someone explain that to me? please

Answer 1

Partial fractions.

Answer 2

1/(x^2(x+1)) = A/x + B/x^2 + C/(x+1)

Answer 3

MALEVOLENCE!!!!

Answer 4

a blast from the past!

Answer 5

ok and why is the A/x minus?

Answer 6

lol?

Answer 7

You have to solve for the constants.

Answer 8

ohhh i see.. ok thanks lemme try it

Answer 9

A/x + B/x^2 + C/(x+1)
Ax(x+1) + B(x+1) + Cx^2 = 1
Ax^2 + Ax + Bx + B + Cx^2 = 1
Ax^2+Cx^2 + Ax+Bx + B = 1
(A+C)x^2 + (A+B)x + B = 0x^2 + 0x + 1

Answer 10

A+C = 0
A+B = 0
B = 1
A = -1
C = -A = 1

Answer 11

Thus:
A/x + B/x^2 + C/(x+1) = (-1/x) + (1/x^2) + (1/(x+1))

Answer 12

ok i got it bahrom, thanks a lot buddy :)

Answer 13

i know i have done this sometimes last year, but i forgot it haha

Answer 14

np sal :)