Question

The image shown in the attachment shows 3 vectors. Determine the components of the sum of three vectors.

(A+B+C)x,(A+B+C)y

Answer 1

here's the image

Answer 2

I think I've gotten this right so far, breaking each vewctor down into components I have A,B, and C.

Answer 3

Next for each x component in each quad I get:

Ax = 44cos(82)=38.84
Ay = 44sin(28)=20.65

Bx= 26.5cos(56) = -14.81
By=26.5sin(56) = 21.96

Cx= 38.84-14.84 = 24.03
Cy=20.65+21.96=-42.61

Is this right so far?

Answer 4

for A and B you are right
but for C:
Cx=0
Cy=-31

Answer 5

so if F is the sum of A,B&C
Fx= Ax+Bx+Cx = 24.03
Fy= Ay+By+Cy = 11.61

Answer 6

how are you getting 0 and -31? I just added (or in this case minus the first two x and y components from A and B and got 24.03 and -42.61

Answer 7

oh wait, nevermind I see.

Answer 8

are you sure that you got it or you want me to explain??

Answer 9

For the components of C, since there is no angle given nor x axis, the x-axis is 0 and the y component is just -31, since its on the bottom y-axis.

The only other thing I'm confused on is getting its magnitude of the sum of three vectors: am I getting the sums of each vector component, x and y respectively and then getting its magnitude or is it just from the vectors themselves?

Answer 10

by adding the x & y components of the three vectors you get the x & y components of F
the magnitude of F = sqrt(24.03^2 +11.61^2) = 26.69
now you know F , Fx & Fy