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OpenStudy (anonymous):

r^2+3r=3

OpenStudy (anonymous):

-3/2 - sqrt21/2 and sqrt21/2 -3/2

OpenStudy (anonymous):

quadratic right use sam formula as before.....kk apply that u will get it...kk

OpenStudy (anonymous):

solve r2 + 3r = 3 ⇒ r=0.7913 , r=-3.791

OpenStudy (anonymous):

you forgot the + or - sign in front of the radical

sam (.sam.):

\[r=\frac{-3+\sqrt{21}}{2}\] and \[r=\frac{-3-\sqrt{21}}{2}\]

sam (.sam.):

whoops\[r=\frac{-b \pm \sqrt{b ^{2}-4ac}}{2a}\]

OpenStudy (anonymous):

Answers in the bottom Site: http://www.algebra.com/algebra/homework/quadratic/Quadratic_Equations.faq.question.327255.html

OpenStudy (anonymous):

weird sam it looks similar to the one in this site too. ;)

OpenStudy (agreene):

or, r^2+3r=3 add 9/4 to both sides r^2+3r+9/4=21/4 (r+3/2)^2=21/4 sqrt and simplify, you will find: -3/2 + sqrt 21/2 and -3/2 - sqrt 21/2 = r of course, you want to simplify: \[r=\frac12(-3\pm\sqrt{21})\]

OpenStudy (anonymous):

hi sam can you help me with placing this in a quadratic formula x^2+18x+4=0

sam (.sam.):

\[x=-9+\sqrt{77}\] and \[x=-9-\sqrt{77}\]

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