r^2+3r=3
-3/2 - sqrt21/2 and sqrt21/2 -3/2
quadratic right use sam formula as before.....kk apply that u will get it...kk
solve r2 + 3r = 3 ⇒ r=0.7913 , r=-3.791
you forgot the + or - sign in front of the radical
\[r=\frac{-3+\sqrt{21}}{2}\] and \[r=\frac{-3-\sqrt{21}}{2}\]
whoops\[r=\frac{-b \pm \sqrt{b ^{2}-4ac}}{2a}\]
Answers in the bottom Site: http://www.algebra.com/algebra/homework/quadratic/Quadratic_Equations.faq.question.327255.html
weird sam it looks similar to the one in this site too. ;)
or, r^2+3r=3 add 9/4 to both sides r^2+3r+9/4=21/4 (r+3/2)^2=21/4 sqrt and simplify, you will find: -3/2 + sqrt 21/2 and -3/2 - sqrt 21/2 = r of course, you want to simplify: \[r=\frac12(-3\pm\sqrt{21})\]
hi sam can you help me with placing this in a quadratic formula x^2+18x+4=0
\[x=-9+\sqrt{77}\] and \[x=-9-\sqrt{77}\]
Join our real-time social learning platform and learn together with your friends!