Two baseballs were hit with the same speed, 25 m/s. One has a theta of 30 degrees and the other had a theta of 60 degrees. What is the time for each of the two baseballs?
Just use the y-component of the velocity for the initial velocity. The ball reaches its highest point at v = 0. Use that for the second velocity. Then the time can be calculated from the equation that has velocities, acceleration (gravity) and time. When you find the time, you have to multiply it by 2, because it takes the same amount of time for it to reach its highest point as it takes for it to fall back to the ground.
Can you be a little more specific on how to solve it?
Do you know what the y-component of the initial velocity is?
|dw:1330384048608:dw| I've never tried to draw a picture. I'm not sure if that's good enough. But the part of the velocity that points straight up is the y component. It is equal to \[V_y = V\sin\theta\]
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