Question

integrate help please

Answer 1

i love integrals, bring it on!

Answer 2

\[a \int\limits_{0}^{1} (dw)/(\sqrt{1-w ^{2}})\]

Answer 3

\[\int\limits_0^1 \left(\sqrt{1-w^2}\right) \, dw=\frac{\pi }{4} \]

Answer 4

and a work out would be helpful too

Answer 5

where does the pi come from

Answer 6

The indefinite integral is:\[\frac{1}{2} \left(w \sqrt{1-w^2}+\text{ArcSin}[w]\right)+C \]

Answer 7

let:
w=sin(u)
dw=cos(u)
thus: int sqrt(1-sin^2(u))= cos u and u= sin^(-1)u
thus:
int cos^2(u) du = int 1/2 cos(2u)+1/2 du (double angle formula)
do those two, and you'll arrive back at:... well what robtoey has, and plug and play from there.

Answer 8

we lost the a

Answer 9

lol didnt notice it... its a constant, so just put an a in the answer :P

Answer 10

i am still confused

Answer 11

Sorry. Overlooked "a"
The answer is:\[a*\frac{ \pi }{4} \]

Answer 12

where is the trig functions coming from?

Answer 13

Refer to the tiff attachment from www.WolframAlpha through Mathematica 8.04 Home Edition.