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Mathematics 17 Online
OpenStudy (anonymous):

integrate help please

OpenStudy (agreene):

i love integrals, bring it on!

OpenStudy (anonymous):

\[a \int\limits_{0}^{1} (dw)/(\sqrt{1-w ^{2}})\]

OpenStudy (anonymous):

\[\int\limits_0^1 \left(\sqrt{1-w^2}\right) \, dw=\frac{\pi }{4} \]

OpenStudy (anonymous):

and a work out would be helpful too

OpenStudy (anonymous):

where does the pi come from

OpenStudy (anonymous):

The indefinite integral is:\[\frac{1}{2} \left(w \sqrt{1-w^2}+\text{ArcSin}[w]\right)+C \]

OpenStudy (agreene):

let: w=sin(u) dw=cos(u) thus: int sqrt(1-sin^2(u))= cos u and u= sin^(-1)u thus: int cos^2(u) du = int 1/2 cos(2u)+1/2 du (double angle formula) do those two, and you'll arrive back at:... well what robtoey has, and plug and play from there.

OpenStudy (anonymous):

we lost the a

OpenStudy (agreene):

lol didnt notice it... its a constant, so just put an a in the answer :P

OpenStudy (anonymous):

i am still confused

OpenStudy (anonymous):

Sorry. Overlooked "a" The answer is:\[a*\frac{ \pi }{4} \]

OpenStudy (anonymous):

where is the trig functions coming from?

OpenStudy (anonymous):

Refer to the tiff attachment from www.WolframAlpha through Mathematica 8.04 Home Edition.

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