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The height of a cell phone tower, AB, is 200 feet. What is the distance, in feet, between the tip of the tower A and a point C on the ground?
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180
?
\[\tan(42)=\frac{BC}{200}\] \[BC=200\tan(42)\]
200 sec 42° 200 sin 42° 200/tan42 200/cosec42
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those are the answer choices
Oh they want hypotenuse
\[\cos(42)=\frac{200}{AC}\] \[AC=\frac{200}{\cos(42)}\] \[AC=200\sec(42)\]
200 sec 42°
thanks
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There is no where in my lessons that tells me how to do this...
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