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Find h' (2) , given h(x) = f(g(x)) , f(u)= u^2 - 1, g(2)=3, and g'(2) -1
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I believe h'(x) = f' (g(x)) g'(x)
yes that is correct
but g(X) is not given...and what is f(u)= u^2 - 1 for..
\[f(u)=u^2-1\] so \[f(g(x))=g^2(x)-1\]
how is g(x) = u..?
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\[f(\zeta)=\zeta^2-1\]
srry..i dont get that... what is that equation...
|dw:1330399812052:dw|
what does this mean?
it says solve
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solve the solution x=_____________
how do u find f' g(x)?
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