Evaluate the limit: lim{h -->0 (4+h)^2-16/h
\[\lim_{h\rightarrow0}\ (4+h)^2-\frac{16}h\] is this the question?
yes! Thanks! I'm new to this..
it's going to be indeterminate, it's approaching infinity from the left and negative infinity from the right
http://www.wolframalpha.com/input/?i=lim+h-%3E0+%28++%284%2Bh%29%5E2-16%2Fh+%29
So the question says this: Evaluate the limit, if it exists. If not, enter "n" below. . . I tried entering n, it told me that it's incorrect..
is there a plus or minus sign above the 0? that indicates left and right directional limits.
no
well, technically it exists, it's just indeterminate. But, then again maybe whoever wrote the question got it wrong when they did it.
hmmmm.. its computer generated through "WebWork" .. I don't know what I should put down as the answer..
well, if the question is what I put as the question... then I have no idea either. because it appears to not want a correct answer.
lol
|dw:1330415369170:dw|
Join our real-time social learning platform and learn together with your friends!