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OpenStudy (anonymous):
http://go.flvs.net/courses/1/flvs_57_3641_2a7b30381160098/ppg/respondus/pool_Geom_3641_0802_07/image0024e849df3.gif
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OpenStudy (anonymous):
,What is the equation of this circle?
Answer
(x + 1)2 + y2 = 2
(x – 1)2 + y2 = 2
(x + 1)2 + y2 = 4
(x – 1)2 + y2 = 4
OpenStudy (anonymous):
I think all 4 are.
OpenStudy (anonymous):
oh! sorry did not look at the picture.
OpenStudy (anonymous):
I am not able to open the pic, can you post the pic here instead of link.
OpenStudy (anonymous):
ya i will hold on
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OpenStudy (anonymous):
OpenStudy (anonymous):
there u go ^^^ XD
OpenStudy (anonymous):
the constants (with opposite sign) with x and y represent the center of the circle. can you find out what is the center of your circle in the picture.
OpenStudy (anonymous):
i think the answer is A am i right it fights the numbers fit in the equation properly
OpenStudy (anonymous):
It should be D. the center is at (1,0) and it goes with opposite sign in the equation. so (x-1)2+(y-0)2=2(radius) ^2
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OpenStudy (anonymous):
oww i see thank you for the help and explaining it
OpenStudy (anonymous):
because the equation does fit this graph thanks so much
OpenStudy (anonymous):
you are welcome, I hope you should be able to tackle similar questions by yorself
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