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Mathematics 16 Online
OpenStudy (anonymous):

Find the slope of the line . (-7,2) (4,6)

OpenStudy (anonymous):

slope is the change in y over the change in x i believe

OpenStudy (anonymous):

For two points (x1,y1) and (x2,y2) the slope is (y2-y1)/(x2-x1)

OpenStudy (anonymous):

sooooo, 6-2 over 4+7

OpenStudy (anonymous):

That's right.

OpenStudy (anonymous):

4 over 11

OpenStudy (anonymous):

you have to solve the problem using (x1, y1) (x2 , x1)

OpenStudy (anonymous):

why are there two x in the second ordered pair...

OpenStudy (anonymous):

6-2 over 6-(-7)

OpenStudy (anonymous):

why.. what happened to the 4?

OpenStudy (anonymous):

thats how you set up the problem now you have to solve it like that

OpenStudy (anonymous):

i think it would be 4/-13 but im not sure

OpenStudy (anonymous):

No, to find slope you have to set it up as rise over run...Meaning you need to pick which ordered pair you want as 1 and which you want as 2. So lets take the first ordered pair as 1 and the second as 2..it would be 6-2 over 4+7. So the answer would be 4 over 11.

OpenStudy (anonymous):

****second not first, I'm sorry. But the answer is still 4 over 11.

OpenStudy (anonymous):

(-4,3) (8,9) can you do this one plz ?

OpenStudy (anonymous):

yeah sure..hold on

OpenStudy (anonymous):

9-3 over 8+4.... 6 over 12 which simplifies to 1/2

OpenStudy (anonymous):

thx imight have another one

OpenStudy (anonymous):

You're welcome, anytime

OpenStudy (anonymous):

I remember hating slope-.- lol(:

OpenStudy (anonymous):

Find the slope between the following points. (-1, 2) and (3, 3)

OpenStudy (anonymous):

1 over 4

OpenStudy (anonymous):

lapretii you should try one yourself.. you have the formula now.

OpenStudy (anonymous):

i get it sometimes but not all the times

OpenStudy (anonymous):

yeah(: I'm a visual learnerrr

OpenStudy (anonymous):

iam trying but im not sure if im getting the rite answers

OpenStudy (anonymous):

so she's helping me

OpenStudy (anonymous):

why don;t you post the question with your attempted answer :)

OpenStudy (anonymous):

itried enough i only have 3more questions left so yea

OpenStudy (anonymous):

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