Question

how do you factor each polynomial : 3n^4-6n^2+9n

Answer 1

plz explain

Answer 2

step by step

Answer 3

how do u do ths

Answer 4

i would factor out a 3n as a first step, because each term is divisible by 3n
\[3n^4-6n^2+9n
=3n(n^3-2n+3)\]

Answer 5

So, start by looking at what you have:
3n^4-6n^2+9n
you only have 1 variable, that's good to know. now just look at the coefficients (the numbers before the variables)

3-6+9
what do we know about these? they are all divisible by 3. Now let's look at the variables with out the coefficients:
n^4-n^2+n
well, we can tell that we can take at most 1 n out of all of these. so let's try taking 3n out of the whole thing, since we know the above:

3n(n^3-3n+3)

looks factored to me.