Question

Using the discriminant, determine the number of real roots of the equation 2x^2 + 3x = 4

Answer 1

get the equation into the form ax^2 + bx + c = 0 by subtracting off a 4 from both sides
then evaluate the discriminant for the equation
\[D_{discriminant} = b^2 - 4ac\]
If the discriminant is greater than 0, you have two real solutions. If it is zero, then you have one real solution. If your discriminant is negative, then you have no real solutions

Answer 2

Old faithful :D thanks , btw i got 41 so there are two real solutions?

Answer 3

Yes, that is correct. The solutions would be (-3 + sqrt(41) )/ 4 and (-3 - sqrt(41) )/ 4, so we can see these are real. :)