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Mathematics 21 Online
OpenStudy (anonymous):

can someone please help me with the last three solutions PLEASE!!!!

OpenStudy (anonymous):

Go ahead.

OpenStudy (anonymous):

I thought you finished them with Karatechopper

OpenStudy (anonymous):

I need solutions for (x^5)^2 and (2)^0 + (2 * 3)^4

OpenStudy (anonymous):

no karatechopper is not replying to me anymore

OpenStudy (anonymous):

(x^5)^2 for exponent raised to exponent you multiply exponents

OpenStudy (anonymous):

so it wou be (x^10

OpenStudy (anonymous):

thats right. and for second question anything power of 0 is 1. solve the second bracket.

OpenStudy (anonymous):

so it would be 8^4

OpenStudy (anonymous):

2^0 is 1 and 2*3 is 6 so it will be 1 + 6^4=??

OpenStudy (anonymous):

7^4

OpenStudy (anonymous):

Nope, you solve 6^4 first, which is 1296+1=1297

OpenStudy (anonymous):

ok the last one is (5^2)^-2

OpenStudy (anonymous):

negative exponential means 1/(that term) so it will be 1/(5^2)^2 and solve it?

OpenStudy (anonymous):

I can not get this I feel so damn stupid :(

OpenStudy (anonymous):

solve whatever is inside the brackets first.

OpenStudy (anonymous):

you seem to be busy. the answer will be 1/625, answered it since I am leaving.

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