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OpenStudy (anonymous):
can someone please help me with the last three solutions PLEASE!!!!
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OpenStudy (anonymous):
Go ahead.
OpenStudy (anonymous):
I thought you finished them with Karatechopper
OpenStudy (anonymous):
I need solutions for (x^5)^2 and (2)^0 + (2 * 3)^4
OpenStudy (anonymous):
no karatechopper is not replying to me anymore
OpenStudy (anonymous):
(x^5)^2 for exponent raised to exponent you multiply exponents
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OpenStudy (anonymous):
so it wou be (x^10
OpenStudy (anonymous):
thats right.
and for second question anything power of 0 is 1. solve the second bracket.
OpenStudy (anonymous):
so it would be 8^4
OpenStudy (anonymous):
2^0 is 1 and 2*3 is 6 so it will be 1 + 6^4=??
OpenStudy (anonymous):
7^4
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OpenStudy (anonymous):
Nope, you solve 6^4 first, which is 1296+1=1297
OpenStudy (anonymous):
ok the last one is (5^2)^-2
OpenStudy (anonymous):
negative exponential means 1/(that term) so it will be 1/(5^2)^2 and solve it?
OpenStudy (anonymous):
I can not get this I feel so damn stupid
:(
OpenStudy (anonymous):
solve whatever is inside the brackets first.
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OpenStudy (anonymous):
you seem to be busy. the answer will be 1/625, answered it since I am leaving.
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