A boat went 75 miles in 2 hours with the current and 4 hours without. What was the boat and current's speed?

Question

anonymous · Answer

d=vt
v=d/t
v(boat)=75mi/4hr=18.75 mi/hr
v(boat)+v(current)=75mi/2hr
18.75mi/hr +v(current)=75mi/2hr
v(current)=75mi/2hr-18.75mi/hr=18.75mi/hr

mathhelp346 · Answer

whats v

anonymous · Answer

velocity

mathhelp346 · Answer

ok

mathhelp346 · Answer

so the speed of the boat is 18.75?

anonymous · Answer

yes the boat and the current travel at the same speed, which is why the time doubles when the current is not flowing

mertsj · Answer

Are you sure you posted the problem correctly?  Typically these problems have the boat going with the current and against the current.

mathhelp346 · Answer

yea thats what is says

mertsj · Answer

Ok.  Good.  Thanks for checking.

mathhelp346 · Answer

i keep getting 28.125 for the boats speed

mertsj · Answer

The boat went 75 miles in 4 hours without any current.  So its speed must be 75/4=18.75

mathhelp346 · Answer

oh ok