Question

3(t − 2) ≥ 9(t + 2) help please

Answer 1

if you need to find t, distribute the 3 and the 9 to get 3t-6 > 9t+18
then add 6 to both side so 3t-6+6 = 3t > 9t + 24
subtract 9t from both side and get -6t > 24 and now divide by -6
you get t > -4

Answer 2

You need to change the direction of the greater than sign when you multiply or divide by a negative number.

So the answer would be \[t \le-4\]

Answer 3

3(t − 2) ≥ 9(t + 2)
t − 2 ≥ 3(t + 2)
t - 2 ≥ 3t + 6
2t <= -8
=> t <= -8/2 = -4