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does anyone know how to solve: ^-3 x ^-128. and show how you obtain answer.
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^-3 x ^-128 ?!!!? It's new to me! Coud you just write it on the board?
\[ \sqrt{-3} \times \sqrt{-128}\]
= i √3 * i √128 = - √3 * √ 2^7 = -8 √6
ok.I got \[\sqrt{3} \pm \sqrt{2}\]
how did you get your answer? please and thanks.
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Which part you don't understand?
pretty much none of it. did you multiply the numbers 3and2 under the radicand to get 6?
Yep!
√ - 128 = √-1 * √ 2^7 = i * √2^6 * 2 = 2^3 i √2 = 8i √2
Is it clear now?
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oh yes, it is. thanks.
No more question?
nope. I'm all set.
That's what makes my day :)
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