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Let f(x)= 3x+1; g(x)=-2x-5 compute the following
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(f composite g)(10)
I am a bit confused on how the write this out
\[f(g(x))=3(-2x-5)+1\] \[f(g(x))=-6x-15+1\] \[f(g(x))=-6x-14\]
\[f(g(10))=-6(10)-14\]
g(10)=-25 f(-25)=-74
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how did you get the -25
g(10), plug in 10 for x in g
the output of g is then substituted for x in f(x)
ok that's right
thank you
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yw
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