A climber goes up the lower part of a 50-foot climbing wall at a rate of 1.2 ft/min. The upper part of the wall is more difficult, and she climbs at 0.8 ft/min. She reaches the top of the wall in 51.5 min. How long did it take her to climb the lower part of the wall? At what height on the wall did her rate change? (Hint: Model each part of the climb with a linear equation, using x for the time and y for distance. Then solve the system of two linear equations for x and y.)

Question

.sam. · Answer

x+y=51.5
1.2x+.8y=50
Then, all you have to do is cancel out one of the variables and solve for one. Then plug it back into equation to solve other variable.

anonymous · Answer

still confused mate so i would make it x=51.5 than plug that into the x and do 51.5 +y=51.5?
and 1.2x/50 than wut i get for x go x +.8y/50?

im bad at this would you mind solving for me :( ill try to help you out on some of ur questions