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OpenStudy (anonymous):
Use the give acceleration function to find the velocity and position vectors. Then find the position at time t = 2. a(t) = tj+tk v(1)=5j r(1) = 0
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OpenStudy (anonymous):
For this problem I know I have to integrate v(t) so that when evaluate at 1 I get 5j, so I got: \ i+t^2/2j+t^2/2k+C, when I plug in 1 I get 2.
sam (.sam.):
Try relate your question with http://answers.yahoo.com/question/index?qid=20110623181323AA2TPb7 This might help
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