Question

∫[(2x)/(x^2+4x+8)] show all work please

Answer 1

I trhink this the final result :ln ( x ^{2}+4x+8)-Arctan(x+1)

Answer 2

I try to write the process...in a few minutes and I will send it to you...

Answer 3

mas-gh90 ... first part is ok the second it seems you've made a mistake

Answer 4

-2tan^-1[(x+2)/2]

Answer 5

Thank you so very much!
Very helpful!

Answer 6

yrw

Answer 7

= ∫ (2x +4) dx/ (x² + 4x + 8)
- 4 ∫ dx/ [(x +2)² + 2²]
= ln (x² + 4x + 8) - 2 arctan (x +2)/2 + C