Question

Evaluate lim 4+6x/1-5x
x->inf

Answer 1

looks like it is asking for the horiztonal asymptote
-6/5

Answer 2

Thanks it's correct!

Answer 3

if you sub in inf to the eq you get right away an inf/-inf situation, so there are a few different ways to do it, and a valid way that also helps when you get to infinite series stuff is to factor out the x's in the numerator and denominator. x(4/x+6)/x(1/x-5).....of course the x's divide out leavind you with (4/x+6)/(1/x-5) the 4/x and the 1/x go to zero as x- to infinity, there fore you have -6/5 like dockworker says. You can also use L'hospital's rule too because it's an indeterminate for right away.