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Calculate g (x) , where g=f-1. State the domain and range of g. Calculate g'(a).
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Find \[f ^{-1}(x)\] Then\[g=f ^{-1}x\] Then differentiate \[g(x)\]to get \[g'(x)\]
Thats what I have been trying but I keep getting an answer different then the answers. Could you complete the problem?
Let y=1/(x-5) y(x-5)=1 xy-5y=1 xy=1+5y x=(1+5y)/y \[f ^{-1}(x)=\frac{1+5x}{x}\] Since \[g=f ^{-1}x\] \[g(x)=\frac{1+5x}{x}\] Differentiate g(x) \[g'(x)=\frac{x(5)-(1+5x)(1)}{x ^{2}}\] \[g'(x)=\frac{-1}{x ^{2}}\] when g'(a) and a=3 \[g'(3)=-\frac{1}{(3)^{2}}\] \[g'(3)=-\frac{1}{9}\]
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