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OpenStudy (anonymous):
still pondering on this one ?
OpenStudy (rulnick):
x>=2
OpenStudy (anonymous):
yep rulnick
OpenStudy (anonymous):
i have a test tomorrow and all of these are essentially the same. I still don't understand how i take a log (base of something small, 2,3,7 or whatever) to x with some sort of inequality to 1 or 0
OpenStudy (rulnick):
if the inequality has left-hand side M and right-hand side N, solve it by replacing the left with b^M and right by b^N, where b is the base of the log.
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OpenStudy (rulnick):
And remember, b^(log_b x) = x.
OpenStudy (rulnick):
Good luck on the test.
OpenStudy (anonymous):
can you explain the "if the inequality has..." part a bit more?
OpenStudy (anonymous):
or even how you sold my original question
OpenStudy (rulnick):
Orig question:
log_2 x >= 1
Doing the steps I suggest:
2^(log_2 x) >= 2^1
x >= 2
That's it!
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OpenStudy (anonymous):
ohhhh, I've been at this for 2 hours... thanks for the new suggestions