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A car completes a journey at an average speed of 40km/h. At what speed must it travel on the return journey if the average speed was 60km/h??
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(40+x)/2 =60. Assuming the average for the round trip was 60km/h
could you explain your method??
The average speed of the total trip is the sum of both the out and back times divded by two. And you know they went 40km/h out, and that the average of the whole trip was 60. So the sum of the out trip and the unknown return trip, divided by 2 has to equal the 60km/h.
I'm assuming here that the out and back distances are the same.
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