A ball is thrown into the air with an initial upward velocity of 60 ft/s. Its height (h) in feet after t seconds is given by the function h = –16t^² + 60t + 6. After about how many seconds will the ball hit the ground?

Question

phi · Answer

The height of the ball when it hits the ground is zero.
So they want you to solve for t :

-16t^2 + 60t +6 = 0

phi · Answer

we can simplify it a bit by dividing both sides by -2
8t^2 -30t -3 =0

anonymous · Answer

thankss.

phi · Answer

you need to use the quadratic formula.

anonymous · Answer

At t=3 seconds, the ball is 42 feet above the ground.