I think THIS is the chain rule
Let y = u**(9/2) and u = 8 x + 1.
what is the derivitive?
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OpenStudy (anonymous):
** means ^
OpenStudy (anonymous):
dy/dx = dy/du * du/dx
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
i mean dy/dx=8
OpenStudy (anonymous):
dy/du = (9/2) u ^ (7/2)
now plug in u = 8x + 1 and multiply by 8
du/dx = 8
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OpenStudy (anonymous):
dy/du=9/2x^1-9/2
OpenStudy (anonymous):
wait do i use the chain rule?
OpenStudy (anonymous):
64x+8
OpenStudy (anonymous):
i think 9/2u^7/2 is wrong
OpenStudy (anonymous):
if y = u^(9/2)
dy/du = (9/2 ) u^ (9/2 - 1 )
this is the power rule: if y=ax^n dy/du = anx^(n-1)
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OpenStudy (anonymous):
i did that but i think 9/2u^7/2 is wrong
OpenStudy (anonymous):
you do use chain rule
dy/dx = dy/du * du/dx
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
i thought you do the power rule inside the chain rule since its in brackets
OpenStudy (anonymous):
ok y = u^(9/2) and u = 8x + 1 right?
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OpenStudy (anonymous):
correct
OpenStudy (anonymous):
dy/dx = (9/2) u ^ (7/2) * 8
= (9/2) (8x + 1)^(7/2) * 8 ( plugging in u = 8x+1)
= 36 ( 8x + 1)^(7/2)
OpenStudy (anonymous):
theres something wrong w/ dy/du
OpenStudy (anonymous):
thats the only problem because du/dx is right
OpenStudy (anonymous):
so the process is f=right but one number is wrong
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OpenStudy (anonymous):
lets look at y = x^n them dy/dx = n x ^ (n-1)
now let u = x and n = 9/2
then y = u^(9/2)
so dy/du = (9/2) u ^(9/2 - 1)
= (9/2) u^ (7/2) because 9/2 - 1 = 9/2 - 2/2 = 7/2