word problem on Radical equation:

Two added to the square root of the product of 4 and a number is equal to 10.

A number is 6more than the principal square root of twice the number.

Question

word problem on Radical equation:

Two added to the square root of the product of 4 and a number is equal to 10.

A number is 6more than the principal square root of twice the number.

anonymous · Answer

2 + sqrt(4x) = 10
x = 16

anonymous · Answer

thanks and the second one?

anonymous · Answer

Not getting a resonable answer. 
the equation should be 
x-6 = sqrt(2x)

anonymous · Answer

It's fine guravS thanks agian. It'shard to do word problem unless you know a pattern for one

anonymous · Answer

$$x=6+\sqrt{2x}$$
(x-6)^2=2x
x^2-14x+36=0
$$x=7+\sqrt{13}, x=7-\sqrt{13}$$