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An angle bisector of a triangle divides the opposite side of the triangle into segments 6 cm and 5 cm long. A second side of the triangle is 6.9 cm long. Find the longest and shortest possible lengths of the third side of the triangle.
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Do you have its illustrated picture, Ducky?
I'm afraid not; the text is all we have to go on.
It's not right triangle?
No, the triangle type isn't specified.
Many thanks!
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Because the bisector line in this case ISN'T perpendicular with base, apply golden rule: a/5 = ( a + 5)/ a ->a² = 5 (a +5) ->a² - 5a -25 = 0 => a = (+5 ± √125 )/ 2 = 8.1
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