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OpenStudy (anonymous):
How do you solve this Luis and Julia have the same number of coins. Luis has only dimes and Julia has only quarters. If Julia has $1.80 more than Luis does, how many coins does each have?
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OpenStudy (anonymous):
Too hard?
OpenStudy (anonymous):
Hello???
OpenStudy (anonymous):
j +1.80 = l .25j = .10l
OpenStudy (anonymous):
sorry my son interrupted me
OpenStudy (anonymous):
j = L -1.80 .25 (L-1.80) = .1L .25L -.45 = .1L .25L -.10L = .45 .15L = .45 L = 3
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OpenStudy (anonymous):
Ok I got, thanks
OpenStudy (anonymous):
.10(3) = .25J .30 = .25J 1.2 = J
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