Question

How do you find integrating factor of differential equation ? Help please!!!

Answer 1

This is the equation

dy/dt = −2y + 2t − 1

Answer 2

integrating factor for firs order DE's
\[y'+p(x)y=q(q) \]is \[e^{\intp(x)dx)\]
and you dont have to worry about the constant

Answer 3

ops
\[e^{\int p(x)dx}\]

Answer 4

\[dy/dt = −2y + 2t − 1 \]
\[y'+2y=2t-1\]
so you p(x) is 2

integrating factor is \[=e^{\int2dx}\]
\[=e^{2x}\]

Answer 5

thank you soo much!!! if you're still there are you able to help me with one more!! :( i'm stuck!

Answer 6

dy/dt− 2y = 3e^(2t)